Solution Set From |2x – 3| + 2 = 9 Is

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The solution set of |2x - 3| + 2 = 9 is

The set of solutions from |2x – 3| + 2 = 9 is

So set solution of | is HP = {-2, 5}.

Discussion Details Question above

If |u| = a, then

  • u = –a for u < 0
  • u = a for u ≥ 0

Also, both sides can be squared to remove the sign score absolutely.

Way to one

|2x – 3| + 2 = 9

|2x – 3| = 9 – 2

|2x – 3| = 7

The second way

2x – 3 = -7 or 2x – 3 = 7

2x = -7 + 3 or 2x = 7 + 3

2x = -4 or 2x = 10

x = -2 or x = 5

HP Gained = {-2, 5}

The Second Way (squaring)

(2x – 3)² = 7²

(2x – 3)(2x – 3) = 7²

4x² – 6x – 6x + 9 = 49

4x² – 12x + 9 = 49

4x² – 12x + 9 – 49 = 0

4x² – 12x – 40 = 0

Simplify by dividing both sides by 4.

x² – 3x – 10 = 0

Factor.

(x – 5)(x + 2) = 0

Obtained x = 5 or x = -2

Obtained HP = {-2, 5}.

Answer details

Class : X

Course : Mathematics

Chapter :  Linear Equations and Inequalities Absolute Value of One Variable

 

Keywords : Linear equation. inequality

 

This is the discussion that we have compiled from various sources by the Katalistiwa team. May be useful.

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