The highest oxidation number of Mn is found in compounds

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The highest oxidation number of Mn is found in compounds

The highest oxidation number of Mn is found in compounds

a. MnCl2
b. K2MnO4
c. Mn2(SO4)3
e.Mn(NO3)2

Answer :

 

The highest Mn oxidation number of +6 is found in potassium manganate (K₂MnO₄).

The highest oxidation number of Mn is found in the compound
a. MnCl₂ ⇒ manganese chloride
b. K₂MnO₄ ⇒ potassium manganate
c. Mn₂(SO₄)₃ ⇒ manganese (III) sulfate
d. Mn(NO₃)₂ ⇒ manganese(II) nitrate

Detailed discussion of the Mn Oxidation Number

Before we look up the oxidation number of Mn in each of the above compounds, it is necessary to recall some of the oxidation numbers of the elements involved, as follows.
1. The oxidation number of group IA elements (alkali metals) is +1.
Thus the oxidation number of K is +1.
2. The oxidation number of group VIIA elements (halogens, non-metals) that are not bound to O (oxygen) is -1.
So the oxidation number of Cl is -1.
3. Compound ions, namely sulfate ions (SO_4^{2-}) It has a total oxidation number according to its charge, which is -2.
4. Ionic compounds, namely nitrate ions (NO_3^{-}) It has a total oxidation number according to its charge, which is -1.
5. The total oxidation number of neutral compounds is zero.

Work on finding the oxidation number (bilox) of Mn

a. MnCl₂
Mn oxidation state + 2(Cl oxidation state) = 0
Bioxal Mn + 2(-1) = 0
∴ \\boxed{Number \\ oxidation \\ Mn = +2}

b. K₂MnO₄
2(K oxidation state) + Mn oxidation state + 4(O oxidation state) = 0
2(+1) + oxidation state of Mn + 4(-2) = 0
2 +bioxal Mn – 8 =0
Bilox of Mn = 8 – 2
∴ \\boxed{Number \\ oxidation \\ Mn = +6}

c. Mn₂(SO₄)₃
2(the oxidation state of Mn)+3(the oxidation state of SO₄) =0
2(biloxMn)+ 3(-2) = 0
2(bioxal Mn)=6
∴ \\boxed{Number \\ oxidation \\ Mn = +3}

d. Mn(NO₃)₂
The oxidation state of Mn +2(the oxidation state of NO₃) =0
Bioxal Mn+2(-1) =0
BiloxMn -2 =0
∴ \\boxed{Number \\ oxidation \\ Mn = +2}

Pay attention to questions c and d, it can also be seen as follows. For a neutral compound with the formula chemical A_mB_n, index n is the charge or oxidation number of A, while index m is the charge or oxidation number of B.
Let's repeat.
c. Mn₂(SO₄)₃
Immediately seen that the oxidation number of sulfate ion compounds is -2 and the oxidation number of Mn is +3.

d. Mn(NO₃)₂
It is immediately seen that the oxidation number of the nitrate ion compound is -1 while the oxidation number of Mn is +2.

Conclusion & Answers

(1). To be able to determine the oxidation number of an element in a compound, it is necessary to understand the magnitude of the oxidation number of other elements in the compound or the magnitude of the charge of an ionic compound and also in terms of its chemical formula.
(2). The oxidation numbers of Mn in MnCl₂ and Mn(NO₃)₂ are the same, namely +2.

Question Details

Class : X
Subject: Chemistry
Category : Redox
Keywords : number, oxidation, oxidation state, charge, Mn, manganese, highest, compounds, ions, potassium, permanganate, chloride, sulfate, nitrate

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